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14. Find the quotient of (9x3 + 12x2 – 23x - 18) = (3x + 2)
a. 3x2 + 2x +9
b. 3x2 + 2x -9
c. 3x2 - 2x -9


Sagot :

Answer:

We think you wrote:

(9x^3+12x^2-23x-18):(3x+2)

This deals with finding the roots (zeroes) of polynomials.Step by Step Solution

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STEP

1

:

Equation at the end of step 1

STEP

2

:

Equation at the end of step

2

:

STEP 3: 9x3 + 12x2 - 23x - 18

Simplify —————————————————————

3x + 2

Checking for a perfect cube :

3.1 9x3 + 12x2 - 23x - 18 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 9x3 + 12x2 - 23x - 18

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -23x - 18

Group 2: 9x3 + 12x2

Pull out from each group separately :

Group 1: (23x + 18) • (-1)

Group 2: (3x + 4) • (3x2)

Step-by-step explanation:

The answer is A

Answer:

a.

Step-by-step explanation:

i hope its help thanks