Sagot :
Answer:
- 32/15y⁵
Step-by-step explanation:
That's all☺️
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1.)
[tex] \frac{10y}{25 {y}^{2} } \div \frac{3 {y}^{4} }{16} = \frac{32}{15 {y}^{5} } [/tex]
2.)
[tex] \frac{21x}{14 {x}^{3} } \div \frac{15}{20 } = \frac{2}{ {x}^{2} } [/tex]
solution: