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[tex] \frac{ 10y}{25y ^{2} } \div \frac{3y ^{4} }{16} \\ \\ \\ \frac{21x}{14x ^{3} } \div \frac{15}{20} \\ \\ [/tex]
with solution sana ​


Sagot :

Answer:

  • 32/15y⁵

Step-by-step explanation:

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1.)

[tex] \frac{10y}{25 {y}^{2} } \div \frac{3 {y}^{4} }{16} = \frac{32}{15 {y}^{5} } [/tex]

2.)

[tex] \frac{21x}{14 {x}^{3} } \div \frac{15}{20 } = \frac{2}{ {x}^{2} } [/tex]

solution:

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