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Determine the mass of NaCl (MM = 58.44 g/mol) needed to prepare a 1.0 molal solution using 25
grams of water as the solvent:​


Sagot :

The mass of NaCl needed = 1.461 g

Further explanation  

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. Concentration shows the amount of solute in a unit of the amount of solvent.  

Molality shows how many moles are dissolved in every 1000 grams of solvent.  

[tex]\tt molality(m)=\dfrac{mol~solute}{kg~solvent}=\dfrac{mol~solute\times 1000}{mass~solvent(g)}[/tex]

Given

1 molal solution

25 g water = 0.025 kg

Required

the mass of NaCl

Solution

Input the value :

molality = (mass of NaCl/molar mass g/mol) / 0.025 kg water

1 = (mass/58.44) / 0.025

mass = 0.025 x 1 x 58.44

mass = 1.461 g

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