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what is the center and radius of x^+y^+8y-84=0


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Answer:

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Algebra Examples

Popular Problems Algebra Find the Center and Radius x^2+y^2-8y=0

x

2

+

y

2

8

y

=

0

Complete the square for

y

2

8

y

.

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(

y

4

)

2

16

Substitute

(

y

4

)

2

16

for

y

2

8

y

in the equation

x

2

+

y

2

8

y

=

0

.

x

2

+

(

y

4

)

2

16

=

0

Move

16

to the right side of the equation by adding

16

to both sides.

x

2

+

(

y

4

)

2

=

0

+

16

Add

0

and

16

.

x

2

+

(

y

4

)

2

=

16

This is the form of a circle. Use this form to determine the center and radius of the circle.

(

x

h

)

2

+

(

y

k

)

2

=

r

2

Match the values in this circle to those of the standard form. The variable

r

represents the radius of the circle,

h

represents the x-offset from the origin, and

k

represents the y-offset from origin.

r

=

4

h

=

0

k

=

4

The center of the circle is found at

(

h

,

k

)

.

Center:

(

0

,

4

)

These values represent the important values for graphing and analyzing a circle.

Center:

(

0

,

4

)

Radius:

4