Sagot :
How many moles of H²O can be made using 1.6 mol NH³?
First write the balance equation for the reaction, which would be:
- N2 + 3 H2 → 2 NH3◀
- This shows the molar ratio of reactants to product, where 1 mol of N2 is equivalent to 2 mol of NH3 and 3 mol of H2 is equivalent to 2 NH3.◀
- Then determine which reactant (N2 or H2) is the limiting reagent.◀
- 6 mol of N2 could generate 6•(2/1)= 12 mol of NH3 while 6 mol of H2 can only generate 6•(2/3)= 4 mol (assuming all reactants react).◀
- H2 is limiting because it generates less product than N2, so you would run out of H2.◀
- Therefore, 4 mol of NH3 would/could be produced.◀