Answer:
1. [tex]CO_{2}[/tex]
Molar Mass: 44.01 [tex]\frac{g}{mol}[/tex]
Mass: 44.01 g
Number of moles: 1 mole
2. [tex]NH_{3}[/tex]
Molar Mass: 17.01 [tex]\frac{g}{mol}[/tex]
Mass: 17.01 g
Number of moles: 1 mole
3. [tex]Al(OH)_{3}[/tex]
Molar Mass: 78 [tex]\frac{g}{mol}[/tex]
Mass: 78 g
Number of moles: 1 mole
Explanation:
1. [tex]CO_{2}[/tex]
From the Periodic table:
Carbon (C) has an atomic mass of 12.01 [tex]\frac{g}{mol}[/tex]
Oxygen (O) has an atomic mass of 15.99 ≈ 16 [tex]\frac{g}{mol}[/tex]
To get the Molar Mass (MM):
MM= Atomic mass of the element * the atoms present in the formula of the element
[tex]MM = 12.01\frac{g}{mol} (1) + 16\frac{g}{mol} (2)\\MM = 44.01 \frac{g}{mol}[/tex]
Mass (g) : 44.01 g
Number of moles: 1 mole
2. [tex]NH_{3}[/tex]
From the Periodic table:
Nitrogen (N) has an atomic mass of 14.01 [tex]\frac{g}{mol}[/tex]
Hydrogen (H) has an atomic mass of 1.00 ≈ 1 [tex]\frac{g}{mol}[/tex]
To get the Molar Mass (MM):
MM= Atomic mass of the element * the atoms present in the formula of the element
[tex]MM = 14.01\frac{g}{mol} (1) + 1\frac{g}{mol} (3)\\MM = 17.01 \frac{g}{mol}[/tex]
Mass (g) : 17.01 g
Number of moles: 1 mole
3. [tex]Al(OH)_{3}[/tex]
From the Periodic table:
Aluminum (Al) has an atomic mass of 26.98 ≈ 27 [tex]\frac{g}{mol}[/tex]
Oxygen (O) has an atomic mass of 15.99 ≈ 16 [tex]\frac{g}{mol}[/tex]
Hydrogen (H) has an atomic mass of 1.00 ≈ 1 [tex]\frac{g}{mol}[/tex]
To get the Molar Mass (MM):
MM= Atomic mass of the element * the atoms present in the formula of the element
[tex]MM = 27\frac{g}{mol} (1) + 16\frac{g}{mol} (3) + 1\frac{g}{mol} (3)\\MM = 78 \frac{g}{mol}[/tex]
Mass (g) : 78 g
Number of moles: 1 mole
