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Answered

if y varies directly as x, and y = 12 when x = 4, find y when x = 12

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ANSWER

[tex] \\ \\ [/tex]

If y varies directly as x and y= 12 when x= 4, find y when x= 12.

[tex] \\ y = kx \\ [/tex]

Evaluate the values

[tex] \\ 12 = k(4) \\ [/tex]

Divide 4 to both sides

[tex] \\ \frac{12}{4} = \frac{k(4)}{4} \\ [/tex]

Cancel both 4 from the right side

[tex] \\ \frac{12}{4} = \frac{k( \cancel{4})}{ \cancel4} \\ [/tex]

Divide

[tex] \\ \boxed{k = 3} \\ \\ [/tex]

Find the y value when x= 12 and use the k= 3 from the first problem.

[tex] \\ y = kx \\ [/tex]

Evaluate values

[tex] \\ y = (3)(12) \\ [/tex]

Multiply 3 by 12

[tex] \\ \large \green{\boxed{ \green{ \sf{y = 36}}}} \\ \\ \\ [/tex]

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