mole to mass

1. Mg(s)+2HCl(ag)➡️MgCl2(ag) +H2(g)
a. How many grams of HCl are consumed by the reaction of 2.50 moles of magnesium?

2. Acetylene gas (C2H2) is produced as a result of the following reaction.
CaC2(s) +2H2O(l)➡️C2H2(g) + Ca (OH)2(aq)

Mole-mole problems
1.N2+3H2➡️2NH3
How many moles of hydrogen are needed to completely react with two moles of nitrogen?

Volume-volume problems
1.N2+3H2➡️2NH3
What volume of hydrogen is necessary to react with five liters of nitrogen tp produce ammonia at STP

Question

Answered

Sagot :

Анонимgo Анонимgo · Answer 1

Solution (Mole to Mass No. 1)

Step 1: Calculate the molar mass of HCl.

molar mass = (1.008 g/mol × 1) + (35.45 g/mol × 1)

molar mass = 36.46 g/mol

Step 2: Determine the mole ratio needed.

mole ratio = 1 mol Mg : 2 mol HCl

Step 3: Calculate the mass of HCl consumed using the mole ratio.

[tex]\text{mass of HCl = 2.50 mol Mg} × \frac{\text{2 mol HCl}}{\text{1 mol Mg}} × \frac{\text{36.46 g HCl}}{\text{1 mol HCl}}[/tex]

[tex]\boxed{\text{mass of HCl = 182 g}}[/tex]

Solution (Mole to Mole No. 1)

Step 1: Determine the mole ratio needed.

mole ratio = 1 mol N₂ : 3 mol H₂

Step 2: Calculate the number of moles of H₂ needed using the mole ratio.

[tex]\text{moles of H₂ = 2 mol N₂} × \frac{\text{3 mol H₂}}{\text{1 mol N₂}}[/tex]

[tex]\boxed{\text{moles of H₂ = 6 mol}}[/tex]

Solution (Volume to Volume No. 1)

Step 1: Determine the volume ratio needed.

mole ratio = 1 L N₂ : 3 L H₂

Step 2: Calculate the volume of H₂ needed using the volume ratio.

[tex]\text{volume of H₂ = 5 L N₂} × \frac{\text{3 L H₂}}{\text{1 L N₂}}[/tex]

[tex]\boxed{\text{volume of H₂ = 15 L}}[/tex]

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