Solve.
(2a + 5)(3a – 2)
[tex] \\ = \tt (2a + 5)(3a – 2) \\ = \tt(2a+5)(3a+−2) \\ = \tt(2a)(3a)+(2a)(−2)+(5)(3a)+(5)(−2) \\ = \tt6 {a}^{2} −4a+15a−10 \\ = \tt\begin{gathered} \boxed{ \large \boxed{\tt{6 {a}^{2} +11a−10}}} \end{gathered} \\ \\ \therefore[/tex]
