k = 180
t = 3 hours
A.
Given: Time(t) = 1.5 hours , Speed(v) = 120 km/h
Find: Constant(k) of variation [inverse].
t = [tex]\frac{k}{v}[/tex]
[tex]\frac{1.5}{1} = \frac{k}{120}[/tex]
k = 180
The constant of variation is equal to 180.
B.
Given: Speed(v) = 60 km/h , Constant(k) = 180
Find: Time(t) it would take to drive back.
t = [tex]\frac{k}{v}[/tex]
t = [tex]\frac{180}{60}[/tex]
t = 3
Therefore, the amount of time it would take to drive back if you were only able to travel at 60 km/ h due to an engine problem is 3 hours.
Hope this helps.
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