Answer:
2Al2O3 → 2Al + 3O2
Molecular mass of Al2O3 = 102 u.
Atomic mass of Al = 27 u
From the stoichiometric equation we can write,
from 102 g of Al2O3 54 g of Al can be recovered.
So, from 34.5 g Al2O3 (54/102)×34.5 g = 18.26 g of Al can be recovered.
Hope, this helps.
