Given:
[tex]P_{1} = \text{0.98 atm}[/tex]
[tex]V_{1} = \text{6 L}[/tex]
[tex]V_{2} = \text{9.50 L}[/tex]
Unknown:
[tex]P_{2}[/tex]
Solution:
[tex]P_{1}V_{1} = P_{2}V_{2}[/tex]
[tex]P_{2} = P_{1} × \frac{V_{1}}{V_{2}}[/tex]
[tex]P_{2} = \text{0.98 atm} × \frac{\text{6 L}}{\text{9.50 L}}[/tex]
[tex]\boxed{P_{2} = \text{0.62 atm}}[/tex]
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