Given:
[tex]V_{1} = \text{635 mL}[/tex]
[tex]T_{1} = \text{34°C + 273.15 = 307.15 K}[/tex]
[tex]T_{2} = \text{25°C + 273.15 = 298.15 K}[/tex]
Unknown:
[tex]V_{2}[/tex]
Solution:
[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]
[tex]V_{2} = V_{1} × \frac{T_{2}}{T_{1}}[/tex]
[tex]V_{2} = \text{635 mL} × \frac{\text{298.15 K}}{\text{307.15 K}}[/tex]
[tex]\boxed{V_{2} = \text{616.4 mL}}[/tex]
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