Sagot :
Answer:
- It required 9 men to fish the same work in 10 days.
Explanation:
- Given:
[tex]days(d)=30\\men(m)=3\\\\d=10\\m=?[/tex]
- Solution:
[tex]m=\frac{k}{d} \\3=\frac{k}{30} \\90=k\\\\\\m=\frac{k}{d}\\m=\frac{90}{10} \\m=9[/tex]
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[tex]days(d)=30\\men(m)=3\\\\d=10\\m=?[/tex]
[tex]m=\frac{k}{d} \\3=\frac{k}{30} \\90=k\\\\\\m=\frac{k}{d}\\m=\frac{90}{10} \\m=9[/tex]
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