what is the center and raduis of 4x²+4y²+8x-32y+4=0
SOLUTION:
[tex]4x {}^{2} + 4y {}^{2} + 8x - 32y + 4 = 0[/tex]
CIRCLE EQUATION
[tex](a,b)²+(y,b)²=r²[/tex]
IS THE CIRCLE EQUATION WITH A RADIUS R, CENTERED AT
[tex](a,b)[/tex]
REWRITE
[tex]4x {}^{2} + 4y {}^{2} + 8x - 32y + 4 = 0[/tex]
IN THE FORM OF STANDARD CIRCLE EQUATION
[tex](x - ( - 1)) {}^{2} + (y - 4) {}^{2} = 4 {}^{2} [/tex]
THEREFOR THE CIRCLE PROPERTIES ARE:
[tex](a,b)=(-1,4),r=4[/tex]
FINAL ANSWER:
[tex]\large\purple{\boxed{Center( -1,4)}}[/tex]
[tex]\large\green{\boxed{Radius = 4}}[/tex]
(√^_^)/
