Sagot :
GIVEN:
[tex]x {}^{2} + y {}^{2} = 400[/tex]
SOLUTION:
[tex]x {}^{2} + y {}^{2} = 400[/tex]
CIRCLE EQUATION
[tex](x - a) + (y - b) {}^{2} = r {}^{2} [/tex]
IS THE CIRCLE EQUATION WITH A RADIUS R, CENTERED AT
[tex](A,B)[/tex]
REWRITE
[tex]x {}^{2} + y {}^{2} = 400[/tex]
IN THE FORM OF THE STANDARD CIRCLE EQUATION
[tex](x - 0) + (y - 0) {}^{2} = 20 {}^{2} [/tex]
THERE FOR THE CIRCLE PROPERTIES ARE:
[tex](a,b)=(0,0),r=20[/tex]
FINAL ANSWER:
[tex]\large\orange{\boxed{Center(0,0)}}[/tex]
[tex]\large\green{\boxed{Radius=20}}[/tex]