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Find the number of permutations of all letters in word Miscellaneous.​

Sagot :

Answer:

7

!

, which is 5040.

Explanation:

Since all letters are unique, we have 7 options for what letter goes first, then the remaining 6 options for what's 2nd, etc.

The total number of permutations is the product of how many options there are for each position:

7

!

=

7

×

6

×

5

×

4

×

3

×

2

×

1

=

5040

If some letters are duplicated, we would divide by the number of ways to permute those duplications, after permuting all the letters.

Example: How many ways can the letters of BANANA be permuted?

We have 1 B, 3 A's and 2 N's. So the number of permutations for BANANA are:

6

!

1

!

×

3

!

×

2

!

=

60

(Notice how the 6 on top equals the sum of the 1, 3, 2 on bottom. This is technically what we did for the letters in NUMBERS above, but since all letters were unique, we did

7

!

1

!

×

1

!

×

1

!

×

1

!

×

1

!

×

1

!

×

1

!

which is the same as the

7

!

as before.)