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what is the value of 3y²+4x-5 when y=1 and y=0?​

Sagot :

Answer:

If y=1 and x=0

[tex]\tt{3y^2+4x-5}[/tex]

[tex]\tt{3(1)^2+4(0)-5}[/tex]

[tex]\tt{3(1)+4(0)-5[/tex]

[tex]\tt{3+0-5[/tex]

[tex]\boxed{\tt{-2}}[/tex]

If x=1 and y=0

[tex]\tt{3y^2+4x-5}[/tex]

[tex]\tt{3(0)^2+4(1)-5}[/tex]

[tex]\tt{3(0)+4(1)-5[/tex]

[tex]\tt{0+4-5}[/tex]

[tex]\boxed{\tt{-1}}[/tex]