A. The resistance in the circuit will not be changed or affected.
If adding a load/s in a series circuit, the resistance will not be changed or affected while the current itself decreased.
If you can see in this example, I will add loads, and we will compute how much current being decreased to the resistance.
LEGEND:
V= referring to Voltage
Ω/R= referring to Resistance
A/I= referring to Current
Let's compute with 1 load and see the result!
Given:
12 V, 4 Ω
The formula for solving current:
I = V/R
The solution and the answer:
12/4 = 3 A
Let's see if I add two loads into the series circuit!
Given:
12 V, 8 Ω
The formula for solving current:
I = V/R
The solution and the answer:
12/8 = 1.5 A
A big difference!
When I add 1 load to the circuit, the current will be 3 A, if I add 2 loads to the circuit, it will result in 1.5 A.
Review!
We see that the current with 1 load (3 A) drops down by 1.5 A with 2 loads.
We can see the current itself decreases when we add more loads to it.
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