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Amatosefrengo
Answered

a cylist going uo kawawa hill at a speed 5m/s slow down to 1m/s in 8 secinds. find his acceleration.​

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Annie2018go

Answer:

a=-0.875

Explanation:

Formula: a=vf-vi

                     t

Solution: a= 1m/s- 8m/s  

                         8s

               a= -7m/s  

                       8s

               a= -0.875 m/s²

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