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If 1000 g of water from Luboc River contains 0.0075 g of Calcium ion, what is the concentration in ppm by mass of calcium ion present in Luboc River? (show your complete solutions)

Sagot :

Given:

[tex]\text{mass}_{solute} = \text{0.0075 g}[/tex]

[tex]\text{mass}_{solvent} = \text{1000 g}[/tex]

Required:

concentration (in ppm)

Solution:

[tex]\text{concentration (in ppm)} = \frac{\text{mass}_{solute}}{\text{mass}_{solute} \: + \: \text{mass}_{solvent}} × 10^{6}[/tex]

[tex]\text{concentration (in ppm)} = \frac{\text{0.0075 g}}{\text{0.0075 g + 1000 g}} × 10^{6}[/tex]

[tex]\boxed{\text{concentration (in ppm) = 7.5 ppm}}[/tex]

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