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1. In how many ways can Aling Daniela arrange 7 different drinks in a refrigerator?


2. In how many ways can 8 students be lined up for a picture taking?


3. Daniel has 5 different Algebra books and 3 different Trigonometry books. In how many ways can he arrange the Algebra books and the Trigonometry books in a shelf?


4. A supervisor wants to assign 5 different tasks to his 5 employees. In how many possible ways can he fix it?

Sagot :

Gracezelle11go

Answer:

PERMUTATION

1. 7P1= 7

2. 8P1= 8

3. 5P3= 60

4.5P5= 120

COMBINATION

1. 7C1= 7

2. 8C1= 8

3. 5C3= 10

4. 5C5= 1

Step-by-step explanation:

1. nPr= n!/(n-r)!                

7P1= 7!/(7-1)!

7P1= 5040/720

7P1= 7 - PERMUTATION

2. nPr= n!/(n-r)!

8P1= 8!/(8-1)!

8P1= 40,320/ 5040

8P1= 8 - PERMUTATION

3. nPr=  n!/(n-r)!

5P3= 5!/(5-3)!

5P3= 120/2

5P3= 60

4. nPr= n!/(n-r)!

5P5= 5!/(5-5)!

5P5=120/1

5P5= 120

COMBINATION

1. nCr= n!/ (n-r)!r!

7C1= 7!/(7-1)!1!

7C1= 5040/720

7C1= 7

2. nCr= n!/ (n-r)!r!

8C1= 8!/(8-1)!1!

8C1= 40,320/ 5040

8C1= 8

3.  nCr= n!/ (n-r)!r!

5C3= 5!/(5-3)!3!

5C3= 120/2(6)

5C3= 120/12

5C3= 10

4. nCr= n!/(n-r)!r!

5C5=  5!(5-5)!5!  

5C5= 5!/0!5!

5C5= 5x4x3x2x1/ 1(5x4x3x2x1)

5C5= 120/120

5C5= 1

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