Answer:
203
Explanation:
We are given the sequence
7, 11, 15, 19
We determine the differences between consecutive terms:
11-7 = 4
15-11 = 4
19-15 = 4
Since the differences are constant, the sequence is arithmetic. Its elements are:
a₁ = 7
d = 4
The rule for the nth term is:
aₙ = a₁ + (n-1) d= 7+4 (n-1) = 7+4n-4 = 4n+3
aₙ= 4n + 3
We find the 50th term or a₅₀ using the formula for the nth term
aₙ = 4n + 3
a₅₀ = 203
Therefore, the 50th term of the sequence is 203.
