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DEFG is a quadrilateral with angle F is congruent to angle D. If angle E = (3x + 11)⁰ and angle G = (5x - 9)⁰ what should be the value of x and the measure of angle E and angle G to make DEFG a parallelogram?



Sagot :

Answer:

x = 11

∠E = 41°

∠G = 41°

Step-by-step explanation:

If ∠D ≈ ∠F ∴ ∠G ≈ ∠E

∠E = (3x + 11)°

∠G = (5x - 9)°

x = ?

∠E = ∠G

3x + 11 = 5x - 9

5x - 3x = 11 + 9

2x = 20

[tex]\frac{2x}{2} = \frac{20}{2}[/tex]

x = 10

Then use substitution method, so it follows:

∠E = 3x + 11

∠E = 3(10) + 11

∠E = 41°

∠G = 5x - 9

∠G = 5(10) -9

∠G = 41°