Can someone please help me out?
Rude =Reported
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Answer:
[tex] \frac{ {a}^{8} {a}^{3} {b}^{-2} }{ {a}^{ - 1} {b}^{ - 5} } = \frac{ {a}^{8} {a}^{3} {ab}^{5} }{ {b}^{2} } = \frac{ {a}^{12} {b}^{5} }{ {b}^{2} } = {a}^{12} {b}^{3} [/tex]