Sagot :
[tex] \large\underline \bold{{SOLUTION}}[/tex]
[tex]\underline{\sf{GIVEN}}[/tex]
- [tex]\sf{10= 2(L+W)}[/tex]
- [tex]\sf{L = x+3}[/tex]
- [tex]\sf{W = x}[/tex]
»Equating the givens and solve by substitution
[tex]\longmapsto\textsf{10=2(L+W)}[/tex]
[tex]\longmapsto\textsf{10=2(x+3+x)}[/tex]
[tex]\longmapsto\textsf{10=2(2x+3)}[/tex]
[tex]\longmapsto\textsf{10=4x+6}[/tex]
[tex]\longmapsto\textsf{10-6=4x}[/tex]
[tex]\longmapsto\textsf{4=4x}[/tex]
[tex]\longmapsto\boxed{\textsf{1=x}}[/tex]
»Again, We will substitute again to get the dimensions.
[tex]\implies\rm{Length = x+3 = 1+3 = \boxed{\sf{4meters}}}[/tex]
[tex]\implies\rm{Width = x = \boxed{\sf{1meter}}}[/tex]
[tex] \large\underline{ \bold{ANSWER}}[/tex]
- [tex]\text{The Length is 4 meters}[/tex]