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Math

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a box contains 4 red,3 white and 2 blue balls.Three balls are draw at random. find out the number of ways of selecting the balls of different colours?

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Answer:

4 red + 3 white + 2 blue = 9

C(n,r) = C(9,3)

= 9!/(3!(9−3)!)

= 9!/(3!×6!)

= 84 ways

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