Find a side of a rhombus whose diagonals are 10 cm and 26 cm. use pythagorean theorem
![Find A Side Of A Rhombus Whose Diagonals Are 10 Cm And 26 Cm Use Pythagorean Theorem class=](https://ph-static.z-dn.net/files/de3/529eca2230a383e1862c65f555150920.png)
[tex] \large\underline \bold{{SOLUTION}}[/tex]
Diagonals meet at the center and forms right-angled triangles. Thus , We will use the pythagorean theorem.
[tex]\sf{D_1 = 10/2 = 5cm}[/tex]
[tex]\sf{D_2 = 26/2 = 13cm}[/tex]
[tex]\longmapsto\textsf{5²+b²=13²}[/tex]
[tex]\longmapsto\textsf{25+b²=169}[/tex]
[tex]\longmapsto\textsf{b²=169-25}[/tex]
[tex]\longmapsto\textsf{b²=144}[/tex]
[tex]\longmapsto\boxed{\textsf{b=12}}[/tex]
All sides are equal , hence the each side measures 12cm.
[tex] \large\underline{ \bold{ANSWER}}[/tex]