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Find a side of a rhombus whose diagonals are 10 cm and 26 cm. use pythagorean theorem

Find A Side Of A Rhombus Whose Diagonals Are 10 Cm And 26 Cm Use Pythagorean Theorem class=

Sagot :

[tex] \large\underline \bold{{SOLUTION}}[/tex]

Diagonals meet at the center and forms right-angled triangles. Thus , We will use the pythagorean theorem.

  • Dividing the diagonals by 2 and forming 4 right triangles.

[tex]\sf{D_1 = 10/2 = 5cm}[/tex]

[tex]\sf{D_2 = 26/2 = 13cm}[/tex]

[tex]\longmapsto\textsf{5²+b²=13²}[/tex]

[tex]\longmapsto\textsf{25+b²=169}[/tex]

[tex]\longmapsto\textsf{b²=169-25}[/tex]

[tex]\longmapsto\textsf{b²=144}[/tex]

[tex]\longmapsto\boxed{\textsf{b=12}}[/tex]

All sides are equal , hence the each side measures 12cm.

[tex] \large\underline{ \bold{ANSWER}}[/tex]

  • [tex]\textrm{12cm}[/tex]
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