Given:
[tex]V_{1} = \text{1.0 L}[/tex]
[tex]T_{1} = \text{20.0°C + 273.15 = 293.15 K}[/tex]
[tex]V_{2} = \text{0.30 L}[/tex]
Unknown:
[tex]T_{2}[/tex]
Solution:
[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]
[tex]T_{2} = T_{1} × \frac{V_{2}}{V_{1}}[/tex]
[tex]T_{2} = \text{293.15 K} × \frac{\text{0.30 L}}{\text{1.0 L}}[/tex]
[tex]T_{2} = \text{87.945 K} [/tex]
[tex]T_{2} = \text{87.945 K} - 273.15[/tex]
[tex]\boxed{T_{2} = -\text{185.2°C}}[/tex]
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