Given:
[tex]V_{1} = \text{10.0 L}[/tex]
[tex]n_{1} = \text{0.08 mol}[/tex]
[tex]n_{2} = \text{0.20 mol}[/tex]
Unknown:
[tex]V_{2}[/tex]
Solution:
[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}[/tex]
[tex]V_{2} = V_{1} × \frac{n_{2}}{n_{1}}[/tex]
[tex]V_{2} = \text{10.0 L} × \frac{\text{0.20 mol}}{\text{0.08 mol}}[/tex]
[tex]\boxed{V_{2} = \text{25.0 L}}[/tex]
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