Sagot :
Solution:
Step 1: Calculate the molar mass of B₂H₆.
molar mass = (10.81 g/mol × 2) + (1.008 g/mol × 6)
molar mass = 27.668 g/mol
Step 2: Determine the mole ratio needed.
mole ratio = 1 mol B₂H₆ : 3 mol O₂
Step 3: Calculate the number of moles of O₂ needed using the mole ratio.
[tex]\text{moles of O₂ = 36.1 g B₂H₆} × \frac{\text{1 mol B₂H₆}}{\text{27.668 g B₂H₆}} × \frac{\text{3 mol O₂}}{\text{1 mol B₂H₆}}[/tex]
[tex]\boxed{\text{moles of O₂ = 3.91 mol}}[/tex]
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