Sagot :
Step-by-step explanation:
[tex] \sqrt{x + 9} = 1 + \sqrt{x} \\ ( \sqrt{x + 9} ) {}^{2} = 1 + ( \sqrt{x} ) {}^{2} \\x + 9 = 1 + x \\ x = 1 + x - 9 \\ x = x - 8[/tex]
correct me if I'm wrong
Step-by-step explanation:
[tex] \sqrt{x + 9} = 1 + \sqrt{x} \\ ( \sqrt{x + 9} ) {}^{2} = 1 + ( \sqrt{x} ) {}^{2} \\x + 9 = 1 + x \\ x = 1 + x - 9 \\ x = x - 8[/tex]
correct me if I'm wrong