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Raymondsayabocisidrogo
Answered

Need po solutions
[tex] \sqrt[4]{x - 1} + 2 = 0[/tex]
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AGboiigo

[tex] \large\underline \bold{{SOLUTION}}[/tex]

[tex]\longmapsto\sf{\sqrt[4]{x - 1} + 2 = 0}[/tex]

[tex]\longmapsto\sf{\sqrt[4]{x - 1}= -2}[/tex]

[tex]\longmapsto\sf{(\sqrt[4]{x - 1})^4 = -2^4}[/tex]

[tex]\longmapsto\sf{x - 1= 16}[/tex]

[tex]\longmapsto\sf{x= 16+1}[/tex]

[tex]\longmapsto\boxed{\sf{x= 17}}[/tex]

[tex] \large\underline{ \bold{ANSWER}}[/tex]

  • The value of x is 17

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