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Need po solutions
[tex] \sqrt{x + 9} = 1 + \sqrt{x} [/tex]


Sagot :

Answer:

Answer :

Solution :

[tex] \sqrt{x + 9} = 1 + \sqrt{x} [/tex]

[tex]x + 9 = 12 \sqrt{x} + x[/tex]

[tex]9 = 1 + 2 \sqrt{x} [/tex]

[tex] - 2 \sqrt{x} = 1 - 9[/tex]

[tex] - 2 \sqrt{x} = - 8[/tex]

[tex] \sqrt{x} = 4[/tex]

[tex]x = 16[/tex]

Step-by-step explanation:

That's. my answer po

Hope it helps po