Solution:
Step 1: Calculate the molar mass of NH₄H₂PO₄.
molar mass = (14.01 g/mol × 1) + (1.008 g/mol × 6) + (30.97 g/mol × 1) + (16.00 g/mol × 3)
molar mass = 115.028 g/mol
Step 2: Calculate the percentage composition of NH₄H₂PO₄.
General Formula:
[tex]\text{percent composition} = \frac{\text{atomic mass of an element × number of atoms in a compound}}{\text{molar mass of compound}} × 100[/tex]
For %N
[tex]\text{\%N} = \frac{\text{14.01 g/mol × 1}}{\text{115.028 g/mol}} × 100[/tex]
[tex]\boxed{\text{\%N = 12.18\%}}[/tex]
For %H
[tex]\text{\%H} = \frac{\text{1.008 g/mol × 6}}{\text{115.028 g/mol}} × 100[/tex]
[tex]\boxed{\text{\%H = 5.26\%}}[/tex]
For %P
[tex]\text{\%P} = \frac{\text{30.97 g/mol × 1}}{\text{115.028 g/mol}} × 100[/tex]
[tex]\boxed{\text{\%P = 26.92\%}}[/tex]
For %O
[tex]\text{\%O} = \frac{\text{16.00 g/mol × 4}}{\text{115.028 g/mol}} × 100[/tex]
[tex]\boxed{\text{\%O = 55.64\%}}[/tex]
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