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formulate the rule in finding the nth term of this sequence 40, 36, 32,30
Has a relation symbol​


Sagot :

• Problem:

Formulate the rule in finding the nth term of this sequence 40, 36, 32, 30.

• Solution:

The given sequence has a common difference of -4, thus, an arithmetic one. Common difference can be obtained when you subtract a term by its preceding term, 36 - 40 = -4, 32 - 36 = -4 in which -4 is the common difference.

Although there's something wrong with the 4th term. Let's say the fourth term is 28.

To formulate a rule for the given sequence, we'll use the formula for arithmetic sequence.

[tex]\large\boxed{\begin{array}{} \tt a_n=a_1+(n-1)d \\ \tt a_n=40+(n-1)( - 4) \\ \tt a_n=40 - 4n + 4 \\ \purple{\tt a_n=44 - 4n}\end{array}}[/tex]

• Answer:

The rule in finding the nth term of the given sequence is 44 - 4n.