Given:
[tex]P_{1} = \text{1 atm}[/tex]
[tex]V_{1} = \text{400 mL}[/tex]
[tex]P_{2} = \text{1.50 atm}[/tex]
Required:
[tex]V_{2}[/tex]
Equation:
[tex]P_{1}V_{1} = P_{2}V_{2}[/tex]
Solution:
[tex]P_{1}V_{1} = P_{2}V_{2}[/tex]
[tex]V_{2} = V_{1} × \frac{P_{1}}{P_{2}}[/tex]
[tex]V_{2} = \text{400 mL} × \frac{\text{1 atm}}{\text{1.50 atm}}[/tex]
[tex]\boxed{V_{2} = \text{266.7 mL}}[/tex]
Answer:
[tex]V_{2} = \text{266.7 mL}[/tex]
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