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Answered

One number exceeds another number by 5 if the sum of thee numbers is 39,find the smaller number

Sagot :

Ylrebmikayacgo

Answer:

The smaller number is 17

Given: x

           x + 5

           39

Solution:

x + (x + 5) = 39

2x + 5 = 39

2x = 39 - 5

2x = 34

x = 17

x + 5 = 22

17 + 22 = 39

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