Answer:
64x3−1
Step-by-step explanation:
[tex] {64x}^{3} - 1[/tex]
Solution :
(4x−1) (16x^2+4x+1)
= (4x−1)(16x^2+4x+1)
= (4x)(16x^2)+(4x)(4x)+(4x)(1)+(−1)(16x^2)+(−1)(4x)+(−1)(1)
= 64x^3+16x^2+4x−16x^2−4x−1
= 64x^3−1
Note : ^ means nakaraised o nakataas.
