FORMULA:
[tex]\textsf{Rule (for arithmetic sequence):} \: \sf a_n = a_1 + (n-1)d[/tex]
[tex]d = a_2 - a_1 \: \textsf{(for arithmetic sequence)}[/tex]
SOLUTION:
[tex]a_n = a_1 + (n-1)d[/tex]
[tex]a_n = -10 + (n-1)d[/tex]
Solving for d,
[tex]d = a_2 - a_1[/tex]
[tex]d = -4 - (-10)[/tex]
[tex]d = 6[/tex]
Plug in the value of d
[tex]a_n = -10 + (n-1)d[/tex]
[tex]a_n = -10 + (n-1)6[/tex]
[tex]a_n = -10 + 6n - 6[/tex]
[tex]a_n = \boxed{6n - 16}[/tex]
ANSWER:
6n - 16
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