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Orquinazacarlryango
Answered

How do you solve the values of the trigonometric ratios of special angles?​

Sagot :

Achadsiinggo

Answer:

Let ABC be an equilateral triangle whose sides have length a (see the figure given below). Draw AD perpendicular to BC, then D bisects the side BC. Now, in right triangle ADB, ∠BAD = 30° and BD = a/2. Hence, we can find the trigonometric ratios of angle 30° from the right triangle ADB.

Kurtmontefalco123go

Answer:

Use Pythagorean theorem... a^2=b^2+c^2 for the SIDES

Use Pythagorean theorem... a^2=b^2+c^2 for the SIDESUse for Angles:

Use Pythagorean theorem... a^2=b^2+c^2 for the SIDESUse for Angles:a^2= b^2+c^2-2bc Cos A

Step-by-step explanation:

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