A taxi running at 30 m/s slowed down uniformly until it stopped in 44 s when a passenger signalled to it. Find the acceleration and the stopping distance.
Distance:1320 meters
Acceleration:1.14m/s²
Solution
Distance formula Time × speed
30×44=1320
Acceleration formula=Vi-Vf÷T
Solution=
=(0-30)÷44
=1.14
1.14m/s²
