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Given quadrilateral ABCD and the exterior angel at each vertex as shown, determine the following sum:
A. a+e=
B. b+f=
C. c+g=
D. d+h=
E. (a+e)+(b+f)+(c+g)+(d+h)=
F. (a+b+c+d)+(e+f+g+h)= ​


Given Quadrilateral ABCD And The Exterior Angel At Each Vertex As Shown Determine The Following SumA AeB BfC CgD DhE AebfcgdhF Abcdefgh class=

Sagot :

Answer:

ABCD= 180°

E= 360°

F= 720°

Step-by-step explanation:

for A, B, C, and D, the given pair of points are collinear which means the sum of their angles sum up to 180°

for E, it asks for the sum of the interior angles. Since the figure is a quadrilateral, it has 4 sides. To find the sum of the exterior angles, we have to use the equation n-2(180) where n is the number of sides. Execute it will show n-2(180)= 4-2(180)=2(180)=360 therefore, the sum of the interior angle is 360

for F, add the total interior and exterior angles which are both 360° so the answer is 720°