QUADRATIC EQUATION
[tex] \sf{Solve \: for \: the \: discriminant \: of \: x²+5x+6=0.}[/tex]
Given Equation
[tex] \tt{ {x}^{2} + 5x + 6 = 0}[/tex]
[tex] \sf{Comparing \: the \: given \: equation \: with}[/tex]
[tex] \tt{a {x}^{2} + bx + c = 0}[/tex]
We get,
[tex] \tt{a = 1} \\ \tt{b = 5} \\ \tt{c = 6}[/tex]
[tex] \: \: \tt{∆ = {b}^{2} - 4ac}[/tex]
[tex] \tt{ = {(5)}^{2} - 4(1)(6)}[/tex]
[tex] \tt{ = 25 - 24}[/tex]
[tex] \tt{ = 1}[/tex]
Thus,
[tex] \large{\tt{∆ = 1}}[/tex]
The value of discriminant is 1
