Answer:
ANSWER
\begin{gathered} \\ \\ \end{gathered}
A. 4x+1 = 2x+7
\begin{gathered} \\ 4x - 2x = 7 - 1 \\ 2x = 6 \\ \frac{2x}{2} = \frac{6}{2} \\ \frac{ \cancel2x}{ \cancel2} = \frac{6}{2} \\ \\ \boxed{x = 3} \\ \\ \end{gathered}
4x−2x=7−1
2x=6
2
2x
=
2
6
2
2
x
=
2
6
x=3
B. 3x+5 = x+15
\begin{gathered} \\ 3x - x = 15 - 5 \\ 2x = 10 \\ \frac{2x}{2} = \frac{10}{2} \\ \frac{ \cancel2x}{ \cancel2} = \frac{10}{2} \\ \\ \boxed{x = 5} \\ \\ \end{gathered}
3x−x=15−5
2x=10
2
2x
=
2
10
2
2
x
=
2
10
x=5
C. 6x+7 = 5x+13
\begin{gathered} \\ 6x - 5x = 13 - 7 \\ \\ \boxed{x = 6} \\ \\ \end{gathered}
6x−5x=13−7
x=6
D. 10x-6 = 7x+9
\begin{gathered} \\ 10x - 7x = 9 + 6 \\ 3x = 15 \\ \frac{3x}{3} = \frac{15}{3} \\ \frac{ \cancel{3}x}{ \cancel3} = \frac{15}{3} \\ \\ \boxed{x = 5} \\ \\ \end{gathered}
10x−7x=9+6
3x=15
3
3x
=
3
15
3
3
x
=
3
15
x=5
E. 5x-1 = 2x+11
\begin{gathered} \\ 5x - 2x = 11 + 1 \\ 3x = 12 \\ \frac{3x}{3} = \frac{12}{3} \\ \frac{ \cancel3x}{ \cancel3} = \frac{12}{3} \\ \\ \boxed{x = 4} \\ \\ \end{gathered}
5x−2x=11+1
3x=12
3
3x
=
3
12
3
3
x
=
3
12
x=4
F. 8 = z/6
\begin{gathered} \\ 8 = \frac{z}{6} \\ (6)(8) = \frac{z}{6} (6) \\ (6)(8) = \frac{z}{ \cancel6} ( \cancel6) \\ \\ \boxed{z = 48} \\ \\ \end{gathered}
8=
6
z
(6)(8)=
6
z
(6)
(6)(8)=
6
z
(
6
)
z=48
G. 11 = x/8
\begin{gathered} \\ 11 = \frac{x}{8} \\ (8)(11) = \frac{x}{8} (8) \\ (8)(11) = \frac{x}{ \cancel8} ( \cancel8) \\ \\ \boxed{x = 88} \\ \\ \end{gathered}
11=
8
x
(8)(11)=
8
x
(8)
(8)(11)=
8
x
(
8
)
x=88
H. b-11 = 11
\begin{gathered} \\ b - 11 = 11 \\ b = 11 + 11 \\ \\ \boxed{b = 22} \\ \\ \end{gathered}
b−11=11
b=11+11
b=22
I. 5z = 4
\begin{gathered} \\ 5z = 4 \\ \frac{5z}{5} = \frac{4}{5} \\ \frac{ \cancel5z}{ \cancel5} =\frac{4}{5} \\ \\ \boxed{z = \frac{4}{5} } \\ \\ \end{gathered}
5z=4
5
5z
=
5
4
5
5
z
=
5
4
z=
5
4
J. 5 = 9s
\begin{gathered} \\ 5 = 9s \\ \frac{5}{9} = \frac{9s}{9} \\ \frac{5}{9} = \frac{ \cancel9s}{ \cancel9} \\ \\ \boxed{s = \frac{5}{9}} \\ \\ \\ \end{gathered}
5=9s
9
5
=
9
9s
9
5
=
9
9
s
s=
9
5
Step-by-step explanation:
hope its help its not my answer but
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