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what is the perimeter of a tricky 60 90 triangle whose shorter leg is 5 cm long​

Sagot :

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in a 30 -60-90  right Δ if the shorter leg  = 5

                                          the hypotenuse  =  10    /  the hypotenuse is twice the length of the shorter leg

  the longer leg =  √3 * 5     /     the longer leg  is  √3 times that of the shorter leg

 perimeter of  Δ   = 5 + 10 +  5√3

                              =  15 + 8.66025

                              =  23.7 ins

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