Sagot :
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in a 30 -60-90 right Δ if the shorter leg = 5
the hypotenuse = 10 / the hypotenuse is twice the length of the shorter leg
the longer leg = √3 * 5 / the longer leg is √3 times that of the shorter leg
perimeter of Δ = 5 + 10 + 5√3
= 15 + 8.66025
= 23.7 ins
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