Answer:
This is a question of Arithmetic Progression
Where the first term a=100
Difference between two consecutive even numbers d=2
And the last term tn=200
We need to find the value of n
Formula is tn=a+(n-1) x d
Substituting the values we get 200=100+(n-1) x2
200-100=2n-2
i.e 100=2n-2
100+2=2n
102/2=n
Therefore the value of n is 51
Step-by-step explanation:
