Sagot :
Answer:
A.
1.x=8
2.x=3
3.AD=27
4.x=11
B.
5.AC=25
6.BD=59
C.
7.x=17
8.x=10
D.
9.HE=88
10.BT=68
Step-by-step explanation:
A.
1.AB=CD
x+6=14
x=14-6
x=8
2.BE=DE
2x=6
2x/2=6/2
x=3
3.AD=BC
4x+15=2x+21
4x-2x=21-15
2x=6
2x/2=6/2
x=3
AD=4x+15
AD=4(3)+15
AD=12+15
AD=27
4.AE=CE
15=x+4
15-4=x
11=x
B.
5.AC=BD
2x+15=3x+10
2x-3x=10-15
-x=-5
-x/-1=-5/-1
x=5
AC=2x+15
AC=2(5)+15
AC=10+15
AC=25
6.AC=BD
5x+14=6x+5
5x-6x=5-14
-x=-9
-x/-1=-9/-1
x=9
BD=6x+5
BD=6(9)+5
BD=54+5
BD=59
C.
7.m<IFE+m<IEF+m<EIF=180
(x+20)+(x+26)+90=180
2x+56+90=180
2x+146=180
2x=180-146
2x=34
2x/2=34/2
x=17
8.m<IMR+m<IRM+m<MIR=180
(4x+20)+(2x+10)+90=180
6x+30+90=180
6x+120=180
6x=180-120
6x=60
6x/6=60/6
x=10
D.
9.BM=EM
x + 12=2x - 20
x-2x=-20-12
-x=-32
-x/-1=-32/-1
x=32
EM=½HE
2x-20=½HE
2(32)-20=½HE
64-20=½HE
44=½HE
(2)44=(2)½HE
88=HE
10.HM=TM
44-x=4+3x
-x-3x=4-44
-4x=-40
-4x/-4=-40/-4
x=10
TM=½BT
4+3x=½BT
4+3(10)=½BT
4+30=½BT
34=½BT
(2)34=(2)½BT
68=BT