[tex]\bold{SOLUTION:}[/tex]
[tex]\textsf{Finding x:}[/tex]
- The sum of the measurements of DO and OG is equal to the measurement of DG.
- Given that DG=60 ft., we will equate the given measurements of DO and OG with 60.
[tex] \quad \qquad \tt DO+OG=60 \\ \\ \qquad\quad\tt (4x - 3 )+ (2x + 21) = 60 \\ \\ \quad \qquad\tt6x+18=60 \\ \\ \qquad\quad\tt 6x=60-18 \\ \\ \qquad\quad\tt 6x=42 \\ \\ \qquad \quad \tt \frac{6x}{6} = \frac{42}{6} \\ \\ \qquad \quad \red{ \boxed{ \tt x = 7}}[/tex]
[tex]\\[/tex]
[tex]\textsf{Finding DO:}[/tex]
- We will substitute the value of x to 4x-3
[tex] \qquad\quad\qquad\tt DO=4x-3 \\ \\ \qquad\quad\qquad\tt DO=4(7)-3 \\ \\ \qquad\quad\qquad\tt DO= 28-3 \\ \\ \qquad\quad\qquad\red{\boxed{\tt DO=25}}[/tex]
[tex]\\[/tex]
[tex]\textsf{Finding OG:}[/tex]
- We will substitute the value of x to 2x+21
[tex] \qquad\quad\qquad\tt OG=2x+21 \\ \\ \qquad\quad\qquad\tt OG=2(7)+21 \\ \\ \qquad\quad\qquad\tt OG= 14+21 \\ \\ \qquad\quad\qquad\red{\boxed{\tt OG=35}}[/tex]
[tex]\\[/tex]
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