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solve for the value of x in
[tex] \frac{18}{11x - 4} = \frac{2}{x} [/tex]


Sagot :

Answer:

Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.

[tex]18x = (11x - 4) \times 2[/tex]

Simplify:

[tex](11x - 4) \times 2[/tex]

Apply the distributive property.

[tex]18x = 11x \times 2 - 4 \times 2[/tex]

Multiply 2 by 11.

[tex]18x = 22x - 4 \times 2[/tex]

Multiply -4 by 2.

[tex]18x = 22x - 8[/tex]

Move all the terms containing x to the left side of the equation.

Subtract 22x from both sides of the equation.

[tex]18x - 22x = - 8[/tex]

Subtract 22x from 18x.

[tex] - 4x = - 8[/tex]

Divide each term by -4x = -8 by -4.

[tex] \frac{ - 4x}{ - 4} = \frac{ - 8}{ - 4} [/tex]

Cancel the common factor.

[tex] \frac{ - 4x}{ - 4} = \frac{ - 8}{ - 4} [/tex]

Divide x by 1.

[tex]x = \frac{ - 8}{ - 4} [/tex]

Divide -8 by -4.

[tex]x = 2[/tex]

Therefore, the answer is 2. Correct me if I’m wrong. :)